WebSolve the equation x^3 - 5x^2 + 2x + 8 = 0 given that - 1 is a zero of f(x) = x^3 - 5x^2 + 2x + 8 The solution set is (Use a comma to separate answers as needed.) Previous question Next question. Get more help from Chegg . Solve it with our Algebra problem solver and calculator. Chegg Products & Services. Cheap Textbooks; WebFind the Roots (Zeros) f(x)=x^3-8. Set equal to . Solve for . Tap for more steps... Add to both sides of the equation. Subtract from both sides of the equation. Factor the left side of the equation. Tap for more steps... Rewrite as . Since both terms are perfect cubes, factor using the difference of cubes formula, where and .
How do you determine the binomial factors of x^3-5x^2+2x+8 ...
WebEasy Solution Verified by Toppr 2x+3y=12 xy=6 8x 3+27y 3 =(2x) 3+(3y) 3 =a 3+b 3=(a+b)(a 2+b 2−ab) 8x 3+27y 3=(2x+3y)((2x) 2+(3y) 2−(2x)(3y)) =(12)[(2+3y) 2−12xy−6xy] =(12)[(12) 2−18(6)] =12[144−108] =12×36 =432. Was this answer helpful? 0 0 Similar questions If a+b=6 and ab=8, find the value of a 3+b 3. Easy View solution > WebQuestion: 2x, + kx2 + kxz – kx4 -8 = 0 Given : 4x, +6x2 + 2kx; – 2kx, = 2k +10 (k is a constant) 2x, + kx, + kx2 - 6x2 = k +4 a. Is there a value of "k" for which the set is homogenous? If so, find it and if not, explain why. b. Find the values of "k" (if there are any) for which the system has: 1. A unique solution. 2. Infinitely many ... morpeth sixth form application
Find k so that x2 + 3x – 4 is a quotient of x3 + kx2 + 2x - 8 …
WebFind the value of k such that (x - 2) is a factor ofx3 + kx2 – kx + 1. 20. (2x3 – kx2 + 5) divided by (x - 2) leaves a remainder of 4. 21. B. 12 9. The expression x3 - kx2 +2x +5 … WebSolution: Given, 3x 2 – 5x + 9 = x 2 – 7x + 3. On simplifying the equation, we have. 2x 2 + 2x + 6 = 0. ⇒ x 2 + x + 3 = 0 (dividing by 2 on both sides) Now, it’s clearly seen that x 2 + x + 3 is a quadratic polynomial. Thus, the given equation is a quadratic equation. Web30 mrt. 2024 · Question 2 (OR 1st question) Find the value of k, for which one root of the quadratic equation kx2 – 14x + 8 = 0 is 2 Given that 2 is a root of the equation So, it must satisfy the equation Putting x = 2 in the equation kx2 – 14x + 8 = 0 k (2)2 – 14 (2) + 8 = 0 k × 4 – 28 + 8 = 0 4k = 28 – 8 4k = 20 k = 20/4 k = 5 So, k = 5 minecraft football field